Okay, so for this problem, you're drawing the E N Z. I summers for each of these are kings and then labeling them as either easy or Z. So this problem starts out pretty straightforward. So when you're drawing your easy I summers you're looking at this carbon and this carbon because used the two carbons attached to the double bond and it doesn't matter which way you draw them. So this carbon on the left is attached to an ethyl group.
So we have an Essel group and a hydrogen. And for this carbon is attached to a hydrogen and a muscle group. So then we can draw the other is summer by keeping one of these the same and then switching the other. So when you're assigning priority for easy I summers, you want to kind of go adam by adam. So if you're looking at this carbon on the left, this carbon is attached, you want to first look at this, these two albums.
So you have a carbon versus a hydrogen. A carbon because it has a higher atomic number has a higher priority. So we'll call this are higher priority on our right. We have a carbon and hydrogen again. So carbon has a higher priority.
And because now we have the same structure on the right, just in a different orientation, we have high Hi. So this is kind of similar to assistant trans. Except consistent trends. You're thinking about the location of the hydrogen in E N. C.
You're thinking about the location of your higher priority groups. So if you're higher priority groups are on the same side, they're going to be easy. You can kind of think of Z same side. It's kind of a little pneumonic device. And if they're on opposite, they're going to be Look at this one now.
So we have this carbon and this carbon are on our double bond. So for our carbon on nowhere. Yeah, it was down a little bit. We have a small group and we have a chlorine on the right, we have a hydrogen and after a group. Thank you chlorine.
Okay. And then we can draw this the other isola here and see how. Okay, so just like the first problem, you want to look at them by adam. So if you're looking at these two on the left, you have a carbon versus a chlorine. So chlorine Has a higher priority because it has an atomic number of 17.
Whereas carbon only has an atomic number of six. So chlorine is going to have your higher priority on the right. You have a carbon versus a hydrogen. So carbon is going to have, as we saw in the first example, carbon has a higher priority than hydrogen and we can translate this to the right. So we have high here and then high here and so on the left are higher priority groups are on the same side, which makes it easy on the right there on opposite sides.
So that makes it me Now, we're getting into a little bit more complicated structures. Okay, so first thing Identiod your two carbons in your double bond and I guess I didn't give myself enough room here, so I'll draw this up here. Okay, so on this carbon on the left, you have an awful group and then you have a bugle group to have C. H three, ch two, ch two, CH two, And then you have Ch three CH 2. And so we'll keep this missing for our carbon on the right, we have this nice approval group and then we also have Hydrogen and two Koreans.
So we have C. Seen CLH two and then we have C ch three ch three. Okay, so here are two double bond structures. So the first thing we want to do is assign priority. So let's look at our carbon on the left.
So what we find is that you want to kind of think of this as alphabetical order. So you want to go adam by adam. So you want to look at Adam one and adam one. In both cases you have a carbon And that carbon is bonded to two hydrogen In a car. So it's two hydrogen and one car.
Then you go to your second atom. This carbon here is attached to three hydrogen. This carbon here is attached to two hydrogen and one carbon. So basically what that tells you is that because if you go one more atom over you go to a carbon versus a hydrogen. This carbon has a higher priority group.
So you're beautiful, has a higher priority than ethel. So let's look at the carbon on the right. So again, the first carbon in each chain. I'm sorry, the first adam and each chain is a carbon. So then you want to look at what these carbons are attached to.
So this carbon is attached to one hydrogen and two carbons. This carbon is attached to two hydrogen and one corinne. So this chlorine has a higher priority than this carbon. So this is going to be a higher priority group. Okay and so again this is going to be easy because our higher priorities are on the same side and this would be e now we're getting even trickier.
So we have this carbon and Miss Cardell. So this carbon we have attached two CH two ch two oh age. And then we have C. Each at all. Here we have carbon triple bonded to carbon and then we have carbon 33 If we draw this out on the right two c.
H 20. Mhm. Okay, so let's look at the carbon in the left first. So if we go carbon by carbon we have this carbon and we have this carbon. So this carbon here, they're both the same.
Right? So then you want to look at what this carbon is attached to. So this carbon is attached to two hydrogen and carbon. So one carbon, two hydrogen, This carbon is attached to one hydrogen and to oxygen. So remember that any time you have multiple bonds. So for example, oxygen bonded to carbon is the same.
Aras thinking of oxygen, carbon and oxygen carbon. I guess that's right two times. So when you think of a double bond, it's really to individual. I guess a better way of drawing this is like this so you can see that carbon is bonded to oxygen. And so because so ignore that part because of these two oxygen's oxygen has a higher priority than a carbon.
So this is going to be our higher priority groups. Was our alcohol. This is our higher priority. Actually change this to read. So now we want to look at the carbons on the right.
So this first carbon is has a triple bonded Al keen Al Qaeda. Sorry. So this is the same as writing may go down carbon carbon carbon. This group here you have a carbon CH, three CH three and ch. Okay, so for this structure You have two carbons that are attached.
In both of these cases you have a carbon That is attached to three cartons. This carbon is attached to three carbons. So then you need to look at the second atom and so this carbon Is attached to one hydrogen and three carbons. So I guess really all of these, you can think of two carbons to hydrogen, one carving. Um But of this group, I'm just going to come down here because I drew it out already.
So we're going to look at this is our second right? So this carbon is attached 23 hydrogen and one carton. So because we have one carbon versus three carbons are all kind has a higher priority than our tribunal group. So if we're looking at these two structures, then our structure on the right is Z. And our structure on the left is me..
